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(2x-1/x^2-2x-3)-(x-5/x^2+4x+3)=x/x^2-9
We move all terms to the left:
(2x-1/x^2-2x-3)-(x-5/x^2+4x+3)-(x/x^2-9)=0
Domain of the equation: x^2-2x-3)!=0
x∈R
Domain of the equation: x^2+4x+3)!=0
x∈R
Domain of the equation: x^2-9)!=0We get rid of parentheses
x∈R
2x-1/x^2-2x-x+5/x^2-4x-x/x^2-3-3+9=0
We multiply all the terms by the denominator
2x*x^2-2x*x^2-x*x^2-4x*x^2-x-3*x^2-3*x^2+9*x^2-1+5=0
We add all the numbers together, and all the variables
3x^2-1x+2x*x^2-2x*x^2-x*x^2-4x*x^2+4=0
Wy multiply elements
3x^2+2x^3-2x^3-1x^3-4x^3-1x+4=0
We do not support expression: x^3
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